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What is the rate at which sound energy is produced by the loudspeaker?

The sound level 23 m from a loudspeaker is 69 dB. What is the rate at which sound energy is produced by the loudspeaker, assuming it to be an isotropic source?
[ ] W

L = 10 log(P1/P0) = 69 dB

log(P1/P0) = 6.9

P1 = (7.94×10^6)P0

P0 = 10^-12 watts

P1 = 7.94 x10^-6 joules per second

This entry was posted on Sunday, January 17th, 2010 at 2:57 am and is filed under loudspeaker. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

One Response to “What is the rate at which sound energy is produced by the loudspeaker?”

  1. PhysicsDude Says:
    January 17th, 2010 at 8:25 am

    L = 10 log(P1/P0) = 69 dB

    log(P1/P0) = 6.9

    P1 = (7.94×10^6)P0

    P0 = 10^-12 watts

    P1 = 7.94 x10^-6 joules per second
    References :

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